Help needed to de-bug card game

Card geme : Acey-Ducey, stuck on line 153, repeat is wrong word,
Can anyone help ? Heres the code below :smile:

--Acey-Deucy

function showIntro() 
print --[[
ACEY-DUCEY IS PLAYED IN THE FOLLOWING MANNER
THE DEALER (COMPUTER) DEALS TWO CARDS FACE UP
YOU HAVE AN OPTION TO BET OR NOT BET DEPENDING
ON WHETHER OR NOT YOU FEEL THE CARD WILL HAVE
A VALUE BETWEEN THE FIRST TWO.
IF YOU DO NOT WANT TO BET, ENTER A $0 BET
]]--
end

-- Initialises the Global BankBalance and Random Number Generator
function initGame()
  bankBalance = 100
    math.randomseed( os.time() )
end

-- shows the card type
function showCard(val)
  local cards={ nil, 2, 3, 4, 5, 6, 7, 8, 9, 10, "JACK", "QUEEN", "KING", "ACE"} 
    return cards[val]
  end
    
-- Displays the current bank balance (global)
function showBalance() 
  print("You Now Have "..bankBalance.." Dollars.")
end

-- Adjusts the global balance
function adjustBalance( amount )
  bankBalance = bankBalance + amount
    showBalance()
end  

-- Generates a random card
function dealCard()
  local nextCardValue = math.random(2,14)
    return nextCardValue
end

-- Deals cards returns a collection of two
function dealCards()
 print("HERE ARE THE NEXT TWO CARDS:")
   local cardValues = {first=dealCard(),second=dealCard()}
     print( "First Card:" .. showCard(cardValues.first) )
       print( "Second Card:" .. showCard(cardValues.second) )  
return cardValues
end

-- Inputs a bet value
function getBet()
  betOK = false
    local betAmount = 0
  -- Loop to get a valid bet or a zero bet
  repeat
  io.write("What is Your Bet ? :");
    local amount = io.read();
      betAmount = tonumber(amount)
  if betAmount==0 then
    print("Chicken!!")
      betOK = true
  end
  if betAmount <= bankBalance then
      betOK = true
    else
      print("Sorry, but you bet too much.")
      print("You have only " .. bankBalance .. " Dollars to bet.")
  end
   until betOK
    return betAmount
end

-- Deals another card and compares values
function playRound( cardValues )
  local playerCard = dealCard()
    local firstCard = cardValues.first 
      local secondCard = cardValues.second 
  print( "Dealer Card" .. showCard(playerCard) )  
    local minValue = math.min( firstCard, secondCard )
      local maxValue = math.max( firstCard, secondCard )
  if playerCard>=minValue and playerCard <=maxValue then
    print("You Win!!!")
    return true
  end
  print("You Lose!!")
  return false
end


function endGameReplay()
  print ("Sorry, but you blue your wad.") 
    io.write("Try Again (Y/N)")
      response = io.read()
  if repsonse == "Y" then
    return true
  else
    print("O.K., Hope you had fun !")  
    return false
  end
end

-- Main Loop ; Here's when the action happens
showIntro()
done = false      -- when true the game loop ends
initGame()
-- Game Loop
repeat
    local cardValues = dealCards()
    local betAmount = getBet()  
    if betAmount == 0 then
      done=true      -- user said they don't want to play anymore
    else
      if playRound(cardValues) then
        adjustBalance( betAmount )
      else
        adjustBalance( -betAmount )    
        -- if no more money then ask to start again
        if bankBalance <= 0 then
          if endGameReplay()==true then
            -- Start again
            initGame() -- reset variables
          end
          done=true
          end
      end
    end

ā€œrepeatā€ isnā€™t a Lua keyword. You can use while(condition) .... end for a loop loop. If condition is false, it will skip running the loop and move on. If condition is always true, it will run until it his a break.

@kendog400 Anytime you post code, put 3 ~'s on a line before and after the code so it shows correctly.

ā€¦

ā€¦

@kendog400 Where did you get the code from. It looks like you copied it from somewhere and you think itā€™s going to work in Codea. Thereā€™s a lot of things in the above code that isnā€™t going to work.

@syntonica repeat is valid. Try this code.

function setup()
    a=0

    repeat
        a=a+1
        print(a)
    until a>15

end

Ack! Sorry about that to the OP. Repeat/until will run at least once while a while may never run.

I never use repeat/until since I never need it. :blush:

Yes, I copied it from a site on-line, I would like to program Card Games, so it is part of a study until I get my roll onā€¦

The card Game was written LUA, but I see now that, it doesent mean it would work in Codeaā€¦In any event Thanks for the Help !

@kendog400 Do a forum search for cards games. You might come up with some interesting things.

@kendog400 If you want to play with card games, maybe this would help some.

function setup()   
    rectMode(CENTER)
    suit={"??","??","??","??"}
    val={"2","3","4","5","6","7","8","9","10","J","Q","K","A"}    
end

function draw()
    background(40, 40, 50)
    cnt=0
    for x=1,4 do
        for y=1,13 do
            cnt=cnt+1
            card(x*100,y*70,cnt,1)
        end
    end
end

function card(x,y,v,sc)      -- x,y position    Card value 1 to 52   sc=size of card
    scale(sc)
    local c=(v-1)%13
    local s=(v-1)//13+1
    fill(255)
    stroke(0, 255, 182, 255)
    strokeWidth(3)
    rect(x,y,45,60)
    fill(255,0,0)
    if s<3 then
        fill(0)
    end
    fontSize(25)
    text(val[c+1],x,y)
    fontSize(14)
    text(suit[s],x-10,y+18) 
    text(suit[s],x+10,y-18) 
    scale(1/sc)
end

It looks like this was designed for a Lua compiler running on windows platform and was not programed for Codea.

Ok, first off, i looked at the original page you got this code from. Youā€™re missing this line until doneat the end of the script. happened to me when i copied it too.

second, it still wonā€™t run - not toally sure why, but i think (just a theory) that Codea wonā€™t allow you to run a script if thereā€™s a repeat or while loop that hasnā€™t finished running. when you do try, it disables the play button and the extra features on the keynoard as well, so maybe a bug there

so replace the repeat, until with function draw() if not done then --[[ the code already there ]] else return end end

ok, so i did that, now im having issues adapting the io read write etc. the real trick is going to be getting io.read to work.

local amount = io.read();

See, what i want is for io.read to bring up the keyboard, but the repeat loop keeps going. soā€¦ ill need to rewritr everything >:(

edit: i give up. this is too hard to convert into codea

I would like to see more youtube type tutorials for codea. Programming isnā€™t for the faint at heart and it takes a lot of brain powerā€¦ 3d max, cinema 4d, zbrush, photoshop all have large followings, and a large amount of youtube tutorials. I would like to see codea with this type of enviorment.

@kendog400 I never liked video tutorials myself. for something like photoshop or krita i can see why it is useful, but when programming i really prefer to have a reference guide in another phone or book while i code. Actually,learning it myself, I still haveā€™t gone into the new Craft stuff yet or even figured ot physics - busy learning everything else.

Hmā€¦ Checklist of what you know? This stuff is lua that I think would be nice to know

  1. What ā€˜Dynamically typedā€™ means. >! Lua is dynamically typed, which means that you can say t={}; and then later say t=ā€˜stringā€™. Variables arenā€™t locked to their type. !<
  2. Given t={a=false,b=false}, set every false value to true using a for loop
  3. How to use a while condition ... do loop
  4. What conditions evaluate as true, and what are false. >! Any value that isnā€™t explicityly false or nil is true. An empty string or tsble evaluates as true.
  5. A repeat .. until loop >! Will always run at least once, it runs first, then checks if condition is true or false, whereas a while loop checks condition first, and so might never run.
  6. What tail calls are. >! Sorry, youā€™re on your own here.
  7. A recursive function >! basically a function that calls itself. e.g. function f(x) return x<10 and f(x+1) or x end print(f(1));
  8. Short circuit logic. VERY useful thing I didnā€™t know until recently. i.e. >! x=1; x = x==2 and 3 or 0; So this is the same as if x==2 then x = 3; else x = 0; endbut easier to write. if you didnā€™t include the ā€˜or 0ā€™ then it would be by default falseā€™, because the or part only runs if the ā€˜conditionā€™ is untrue
  9. multiple assignment. can you guess what this prints? local a,b,c = 1,2; print(a,b,c) >! 1,2,nil
  10. How to write your own iterator function. You know how for loops call psirs, or ipairs? these sre actual functions and you can write your own

ā€¦

@kendog400 Hereā€™s my above code with a few modifications to shuffle a deck of cards. My suggestion is to look over this code and try to understand whatā€™s happening. Thatā€™s an easy way to learn.

displayMode(FULLSCREEN)
supportedOrientations(PORTRAIT_ANY)

function setup()   
    rectMode(CENTER)
    suit={"??","??","??","??"}
    val={"2","3","4","5","6","7","8","9","10","J","Q","K","A"}  
    deck={}
    shuffle()
end

function draw()
    background(40, 40, 50)
    fill(255)
    text("Tap screen to shuffle",WIDTH/2,HEIGHT-50)
    cnt=0
    for x=1,4 do
        for y=1,13 do
            cnt=cnt+1
            card(x*100,y*70,deck[cnt],1)
        end
    end
end

function touched(t)
    if t.state==BEGAN then
        shuffle()
    end
end

function shuffle()
    local tab={} 
    for z=1,52 do
        table.insert(tab,z)
    end
    deck={}
    for z=1,52 do
        d=math.random(#tab)
        table.insert(deck,tab[d])
        table.remove(tab,d)
    end   
end

function card(x,y,v,sc)      -- x,y position    Card value 1 to 52   sc=size of card
    scale(sc)
    local c=(v-1)%13
    local s=(v-1)//13+1
    fill(255)
    stroke(0, 255, 182, 255)
    strokeWidth(3)
    rect(x,y,45,60)
    fill(255,0,0)
    if s<3 then
        fill(0)
    end
    fontSize(25)
    text(val[c+1],x,y)
    fontSize(14)
    text(suit[s],x-10,y+18) 
    text(suit[s],x+10,y-18) 
    scale(1/sc)
end

Thank You for the helpā€¦