```
if Body.info==4 or Body.info==5 then
```

```
if Body.info==4 or 5 then
```

```
if Body.info==4 or Body.info==5 then
```

```
if Body.info==4 or 5 then
```

The first “if” statement works correctly, the second “if” statement doesn’t. See the example. I’m not sure exactly what the second “if” statement is doing without seeing the low level code.

```
function setup()
for z=1,10 do
if z==4 or z==5 then
print("equal 4,5 ",z)
end
if z==7 or 8 then
print("equal 7,8 ",z)
end
end
end
```

No, they aren’t the same. The second expands to:

```
if Body.info == 4 or "5 is neither false nor nil" then
```

The parts of a conditional are completely separate.

Would this work?

```
if Body.info == (4 or 5) then ... end
```

No. `(4 or 5)`

expands to “if 4 is not false or nil then 4 else 5” so `if Body.info == (4 or 5) then ... end`

is equivalent to `if Body.info == 4 then ... end`

.

It can be useful to have lua on your desktop to experiment with these things. For the above, I tried:

```
for a=1,10 do
if a == (3 or 4) then
print(a .. " matches")
end
end
```

and got just:

```
3 matches
```

cool. thanks for clarifying!