come on, try a little harder! :-?
It is the average of the times displayed?
Because each time Ti is proportionnal to the Mo to load: Mi = B/n x Ti, with B bandwith, and n the number of files loading.
The total time is simply total of Mo divided by bandwidth (M1+M2+…+Mn)/B.
Replacing for Mi give the result.
You are too quick, Jmv38. My explanation for the result is that if you downloaded them one at a time, their times would all be N times faster, so it would be the total times / N, or the average.