I was wondering how I could compare the x,y cords of values in a single table. Is that possible, and if so how would I do it? Thanks! 
Could you post an example?
Well, I don’t have the code really yet, I was just thinking conceptually of having a table with all of my rectangles in sort of a grid and if there are three in a row of the same color they are removed. Kind of like candy crush
Sorry its not much to go off of 
Assuming you have a 3x3 2D table, you can compare their values easily enough by looping through all the rows and columns
Comparing two table entries is just like tbl[i][j] == tbl[m][n]
Ok Thanks!
Whenever I try it I just get a nil error. How many loops would I need to compare three entries?
Depends on how you are finding those entries etc - show us your code?
for i = 1, table.maxn(blocks) do
if blocks[i]:collision(ball) then
blocks[i].clr = ball.clr
if blocks[i].clr == blocks[i + 1].clr and blocks[i].clr == blocks[i-1].clr then
table.remove(blocks,i)
table.remove(blocks,i + 1)
table.remove(blocks,i - 1)
end
if table.maxn(blocks) == 0 then
nextLevel()
end
break
end
end
tell me if you need more, the blocks[i].clr calls a self.clr which is a number value from a brick class that just makes the bricks and changes colors. If you need that let me know.
if you’re getting a nil error, are you sure that blocks[i], [i+1] or [i-1] exists? you can always do
print( blocks[i] ) to see if it’s an actual object. it’ll print “table 0x0df2ad5” for example, if it’s a valid table in memory.
ok thanks ill check it!
Also, instead of table.maxn(blocks), use
for i = 1,#blocks do
--Do Something
end
end
Whats the difference?
And with this sort of code, how would I make a match 3 in a row style game?
Maybe try this?
for i = 2, #blocks - 1 do
if blocks[i]:collision(ball) then
blocks[i].clr = ball.clr
if blocks[i].clr == blocks[i + 1].clr and blocks[i].clr == blocks[i-1].clr then
table.remove(blocks,i)
table.remove(blocks,i + 1)
table.remove(blocks,i - 1)
end
if #blocks == 0 then
nextLevel()
end
break
end
end
I formatted it, too.
@compactbear @CodeaNoob’s code is almost exactly the same as your old code. Using # to get the length of a table is a bit faster, I think. Anyways, most people don’t use table.maxn().
OK. Thanks. This looks good ill give it a shot!
I think #tbl and table.maxn(tbl) are equally fast, rather typing # is faster and so it is more commonly used. Neither work on indexed tables, but it is easy to write a function that does
That’s what I said… ;)) ;)) ;))